A flowerpot falls from a window with a height of 6.50m. With which speed does the flowerpot hit the ground?
Solution
Since energy is fully conserved, we can use the formula
$$v = \sqrt{2gh}$$
for calculating the speed by inserting $h=6.5\,\mathrm{m}$ and $g=9.81\,\mathrm{m/s^2}$. This results in
$$v \approx 11.3\,\mathrm{m/s}$$