Newton versus Coulomb

For solving this question, we will use the formula of Coulomb's law $$F_C = \frac{e^2}{4\pi\varepsilon_0 r^2}$$ and Newton's law of gravitation: $$F_G = G\frac{m_p m_e}{r^2}$$ When dividing $F_C$ by $F_G$, the distance $r$ cancels out and only the consts remain: $$\frac{F_C}{F_G} = \frac{e^2}{4\pi\varepsilon_0Gm_pm_e}\approx 2.1\cdot 10^{39}$$ This result means that the electrical force between a proton and an electron is almost 40 orders of magnitude higher than the gravitation force between them.