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Pneumatic Lighter

In a pneumatic lighter, the volume of an air-gasoline mixture is rapidly reduced to 10%. The original temperature is $20^\circ$C. To what value does it increase after compression? Solution

The volume decreases from $V_1$ to $V_2 = 0.1V_1$. Therefore, the temperature increases to $$T_2 = T_1\left(\frac{V_1}{V_2}\right)^{\kappa-1} = 10^{\kappa-1} T$$ For air, we can consider $\kappa\approx 7/5$. From that it follows for the temperature $T_2 = 736\,\mathrm{K}=463^\circ\mathrm{C}$

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Last modified: 2022-10-01 21:00:20 by mustafa

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Pneumatic Lighter